getdate

(PHP 4, PHP 5, PHP 7)

getdate取得日期/时间信息

说明

array getdate ([ int $timestamp = time() ] )

返回一个根据 timestamp 得出的包含有日期信息的关联数组 array。如果没有给出时间戳则认为是当前本地时间。

参数

timestamp

可选的 timestamp 参数是一个 integer 的 Unix 时间戳,如未指定,参数值默认为当前本地时间。也就是说,其值默认为 time() 的返回值。

返回值

返回一个根据 timestamp 得出的包含有日期信息的关联数组 array。 返回的关联数组中的键名单元有以下几个:

返回的关联数组中的键名单元
键名 说明 返回值例子
"seconds" 秒的数字表示 059
"minutes" 分钟的数字表示 059
"hours" 小时的数字表示 023
"mday" 月份中第几天的数字表示 131
"wday" 星期中第几天的数字表示 0 (周日) 到 6 (周六)
"mon" 月份的数字表示 112
"year" 4 位数字表示的完整年份 比如: 19992003
"yday" 一年中第几天的数字表示 0365
"weekday" 星期几的完整文本表示 SundaySaturday
"month" 月份的完整文本表示,比如 January 或 March JanuaryDecember
0 自从 Unix 纪元开始至今的秒数,和 time() 的返回值以及用于 date() 的值类似。 系统相关,典型值为从 -21474836482147483647

范例

Example #1 getdate() 例子

<?php
$today 
getdate();
print_r($today);
?>

以上例程的输出类似于:

Array
(
    [seconds] => 40
    [minutes] => 58
    [hours]   => 21
    [mday]    => 17
    [wday]    => 2
    [mon]     => 6
    [year]    => 2003
    [yday]    => 167
    [weekday] => Tuesday
    [month]   => June
    [0]       => 1055901520
)

参见

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User Contributed Notes 5 notes

up
14
vimal866 at gmail dot com
1 year ago
Andre's code will throw an error. for the following line
   
     $d = $todayh[mday];
     $m = $todayh[mon];
     $y = $todayh[year];

"Notice : Undefined constant mday ,mon,year"

As is, it was looking for constants called mday, mon, year etc. When it doesn't find such a constant, PHP interprets it as a string.

like any other request it should be wrapped in quotes like this

     $d = $todayh['mday'];
     $m = $todayh['mon'];
     $y = $todayh['year'];
up
17
Yura Pylypenko (plyrvt at mail dot ru)
14 years ago
In addition to canby23 at ms19 post:
It's a very bad idea to consider day having 24 hours (86400 secs), because some days have 23, some - 25 hours due to daylight saving changes. Using of mkdate() and strtotime() is always preferred. strtotime() also has a very nice behaviour of datetime manipulations:
<?php
echo strtotime ("+1 day"), "\n";
echo
strtotime ("+1 week"), "\n";
echo
strtotime ("+1 week 2 days 4 hours 2 seconds"), "\n";
echo
strtotime ("next Thursday"), "\n";
echo
strtotime ("last Monday"), "\n";
?>
up
0
andre at anlex dot co dot za
10 years ago
I thought best to show a posseble way to go about bypassing the end month issue where the first day in a new month will have the monday of the week that it falls in - in the old month. Use the numbering of days as the constant and work you way from there.

Example:
<?php
//-----------------------------
$now = time();
$num = date("w");
if (
$num == 0)
{
$sub = 6; }
else {
$sub = ($num-1); }
$WeekMon  = mktime(0, 0, 0, date("m", $now)  , date("d", $now)-$sub, date("Y", $now));    //monday week begin calculation
$todayh = getdate($WeekMon); //monday week begin reconvert

$d = $todayh[mday];
$m = $todayh[mon];
$y = $todayh[year];
echo
"$d-$m-$y"; //getdate converted day

?>

Allot less code makes everyone happy..
up
-43
timforte at gmail dot com
9 years ago
It's worth noting that this is local time, not UTC/GMT - gmgetdate doesn't exist :(.

The most logical way to handle date arithmetic without hitting DST problems is to work in UTC...

<?php
function add_days($my_date,$numdays) {
 
$date_t = strtotime($my_date.' UTC');
  return
gmdate('Y-m-d',$date_t + ($numdays*86400));
}
?>

[it's even faster if you use gmmktime instead of strtotime]
up
-63
eric dot schultz at NOSPAM dot CyVon dot com
8 years ago
Here is another gmgetdate that is a little faster/suscint (no loops).

<?php
function gmgetdate2($ts = null){
       
$k = array('seconds','minutes','hours','mday',
               
'wday','mon','year','yday','weekday','month',0);
        return(
array_combine($k,split(":",
               
gmdate('s:i:G:j:w:n:Y:z:l:F:U',is_null($ts)?time():$ts))));
        }
?>

It also returns the values in the same order as getdate.
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